Question

raiz da equação 2x²-12x-8=0?????
urgente!!!

Answer 1

$2x^2-12x-8=0\\ \\ x^2-6x-4=0\\ \\ \Delta=(-6)^2-4.1.(-4)=36+16=52\\ \\ x=\frac{6\pm\sqrt{52}}{2.1}=\frac{6\pm2\sqrt{13}}{2}=3\pm\sqrt{13}$