Question

Raiz cubica de
$\sqrt[3]{7}$
$\sqrt[3]{70}$
$\sqrt[3]{130}$
$\sqrt[3]{ - 30}$
$\sqrt[3]{1253}$
​

Answer 1

Resposta:

1728/2=864

864/2=432

432/2=216

216/2=108

108/2=54

54/2=27

27/3=9

9/3=3

3/3=1

1728 = 2^3.2^3.3^3

Assim sendo, substitua a \sqrt[3]{1728}

3

1728

por \sqrt[3]{2^{3}.2^{3}.3^{3} }

3

2

3

.2

3

.3

3

,

corte os expoentes da raiz cúbica e você obterá 2.2.3, que é igual a 12.

Ou seja, 12 = \sqrt[3]{1728}

3

1728

.

3375/3

1125/3

375/3

125/3

25/5

5/5

1

\sqrt[3]{3375}

3

3375

=3^3.3.5^2

\sqrt[3]{3^{3}.3.5^{2} }

3

3

3

.3.5

2

3\sqrt[3]{75}3

3

75

50625/3

16875/3

5625/3

1875/3

625/3

125/5

25/5

5/5

1

3^4.3.5^3

3\sqrt[4]{3.5^{3} }

4

3.5

3

3\sqrt[4]{375}

4

375