Question

radiciação?


Alguém sabe?​

Answer 1

Explicação passo-a-passo:

$1)$

$\sqrt{ \sqrt{5} }$

$\sqrt[2 \times 2]{5}$

$\sqrt[4]{5}$>>>resposta

$2)$

$\sqrt[3]{ \sqrt{7} }$

$\sqrt[3 \times 2]{7}$

$\sqrt[6]{7}$>>>resposta

$3)$

$\sqrt[]{ \sqrt[4]{64} }$

$\sqrt[2 \times 4]{64}$

$\sqrt[8]{64}$

$\sqrt[8]{2 {}^{6} }$

$\sqrt[8 \div 2]{2 {}^{6 \div 2} }$

$\sqrt[4]{2 {}^{3} }$>>>resposta

$4)$

$\sqrt[4]{ \sqrt[3]{x {}^{12} } }$

$\sqrt[4 \times 3]{x {}^{12} }$

$\sqrt[12]{x {}^{12} }$

$x$>>>resposta

$5)$

$\sqrt{ \sqrt{15} }$

$\sqrt[2 \times 2]{15}$

$\sqrt[4]{15}$>>>resposta

$6)$

$\sqrt{ \sqrt{x {}^{4} } }$

$\sqrt[2 \times 2]{x {}^{4} }$

$\sqrt[4]{x {}^{4} }$

$x$>>>resposta

$7)$

$\sqrt[]{ \sqrt[3]{ \sqrt{12} } }$

$\sqrt[2 \times 3 \times 2]{12}$

$\sqrt[12]{12}$>>>resposta

$8)$

$\sqrt[3]{ \sqrt[]{ \sqrt[4]{6} } }$

$\sqrt[3 \times 2 \times 4]{6}$

$\sqrt[24]{6}$>>>resposta

$9)$

$\sqrt{ \sqrt{ \sqrt{10} } }$

$\sqrt[2 \times 2 \times 2]{10}$

$\sqrt[8]{10}$>>>resposta

$10)$

$\sqrt[]{ \sqrt[6]{x {}^{12} } }$

$\sqrt[2 \times 6]{x {}^{12} }$

$\sqrt[12]{x {}^{12} }$

$x$>>>resposta