Question

racionalize:
$a)\frac{1-\sqrt{3} }{\sqrt{3} } \\\\b)\frac{3-\sqrt{2} }{\sqrt{2} } \\\\c)\frac{1}{3-\sqrt{6} }$

Answer 1

Oie, Td Bom?!

a)

$\frac{1 - \sqrt{3} }{ \sqrt{3} }$

$\frac{1 - \sqrt{3} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$\frac{(1 - \sqrt{3}) \sqrt{3} }{ \sqrt{3} \sqrt{3} }$

$\frac{ \sqrt{3} - 3 }{3}$

b)

$\frac{3 - \sqrt{2} }{ \sqrt{2} }$

$\frac{3 - \sqrt{2} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }$

$\frac{(3 - \sqrt{2}) \sqrt{2} }{ \sqrt{2} \sqrt{2} }$

$\frac{3 \sqrt{2} - 2}{2}$

c)

$\frac{1 }{3 - \sqrt{6} }$

$\frac{1}{3 - \sqrt{6} } \times \frac{3 + \sqrt{6} }{3 + \sqrt{6} }$

$\frac{1(3 + \sqrt{6} )}{(3 - \sqrt{6} ) \times (3 + \sqrt{6} )}$

$\frac{3 + \sqrt{6} }{9 - 6}$

$\frac{3 + \sqrt{6} }{3}$

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