Matemática, perguntado por thataisabelle, 11 meses atrás

Racionalize os denominadores e marque a opção correta

Anexos:

Soluções para a tarefa

Respondido por GeBEfte
8

I.

\frac{7}{\sqrt{7}+2}\\\\\frac{7}{\sqrt{7}+2}.\frac{\sqrt{7}-2}{\sqrt{7}-2}\\\\\frac{7\;.\;(\sqrt{7}-2)}{\sqrt{7}^2+2\sqrt{7}-2\sqrt{7}-2^2}\\\\\frac{7(\sqrt{7}-2)}{7-4}\\\\\frac{7(\sqrt{7}-2)}{3}


II.

\frac{1}{\sqrt[5]{\sqrt{16}}}\\\\\frac{1}{\sqrt[5]{4}}\\\\\frac{1}{\sqrt[5]{4}}.\frac{\sqrt[5]{4}^4}{\sqrt[5]{4}^4}\\\\\frac{\sqrt[5]{4}^4}{\sqrt[5]{4}^5}\\\\\frac{\sqrt[5]{4^4}}{4}\\\\\frac{\sqrt[5]{256}}{4}


III.

\frac{7}{2\sqrt{3}}\\\\\frac{7}{2\sqrt{3}}.\frac{\sqrt{3}}{\sqrt{3}} \\\\\frac{7\sqrt{3}}{2.\sqrt{3}^2}\\\\\frac{7\sqrt{3}}{2\;.\;3}\\\\\frac{7\sqrt{3}}{6}

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