Question

Racionalize os denominadores das seguintes expressões: me ajudem por favorrrr

Answer 1

Oie, Td Bom?!

e)

$= \frac{2 - 2 \sqrt{2} }{2 - \sqrt{2} } \\ = \frac{ \sqrt{2} \: . \: ( \sqrt{2} - 2) }{ - ( \sqrt{2} - 2)} \\ = \sqrt{2} \: . \: ( - 1) \\ = - \sqrt{2} \: . \: 1 \\ = - \sqrt{2}$

f)

$=\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ =\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \: . \: \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ = \frac{( \sqrt{3} - \sqrt{2} ) \: . \: ( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2} ) \: . \: ( \sqrt{3} - \sqrt{2} )} \\= \frac{( \sqrt{3} - \sqrt{2} ) \: . \: ( \sqrt{3} - \sqrt{2} )}{3 - 2} \\ =\frac{( \sqrt{3} - \sqrt{2}) \: . \: ( \sqrt{3} - \sqrt{2} )}{1} \\= ( \sqrt{3} - \sqrt{2} ) \: . \: ( \sqrt{3} - \sqrt{2} ) \\= ( \sqrt{3} - \sqrt{2} ) {}^{2} \\= 3 - 2 \sqrt{6} + 2 \\= 5 - 2 \sqrt{6}$

Att. Makaveli1996