Question

racionalize os denominadores :
a) 8/√3=
b) 5√2/√6=
c) 2√3/3√5=
d) 6/√2+1=
e) 10/√5+4=

Answer 1

8/√3 * √3/√3 = (8√3)/√9 = (8√3)/3

(5√2)/√6 = (5√2)/(√2*√3) = 5/√3 * √3/√3 = 5√3 / √9 = 5√3 / 3

(2√3 / 3√5) * √5/√5
2√15 / 3*√25 = 2√15/3*5 = 2√15/15

6 / (√2+1) * (√2-1 / √2-1) = (6√2-6)/(√4-1) =
(6√2-6)/(2-1) = (6√2-6)/1 = 6√2-6

(10 / √5+4) * (√5-4 / √5-4) = (10√5-40)/(√25-16)
(10√5-40)/(5-16) = (10√5-40)/-11