Question

racionalize o denominador
[tex] \frac{9}{9 \sqrt[5]{12
​

Answer 1

Resposta:

$\dfrac{\sqrt[5]{12^4}}{12}$

Explicação passo-a-passo:

$\dfrac{9}{9\sqrt[5]{12}}=\dfrac{1}{\sqrt[5]{12}}=\dfrac{1\times \sqrt[5]{12^4}}{\sqrt[5]{12}\times \sqrt[5]{12^4}}=\dfrac{\sqrt[5]{12^4}}{\sqrt[5]{12^5}}=\dfrac{\sqrt[5]{12^4}}{12}$