Question

racionalize o denominador:

$10\\5-\sqrt{2}$

Answer 1

$\frac{10}{5 - \sqrt{2} } \times \frac{ \sqrt{2} }{ 5 + \sqrt{2} } \\ \frac{50 + 10 \sqrt{2} }{25 - 2} = \frac{50 + 10 \sqrt{2} }{23}$

Answer 2

$\frac{10}{5-\sqrt{2}}$ = $\frac{10}{5-\sqrt{2} } . \frac{5+\sqrt{2} }{5+\sqrt{2} } = \frac{50+10\sqrt{2} }{25-2}= \frac{50+10\sqrt{2} }{23}$