Question

Racionalize o denominador de:

Answer 1

$a) = \frac{6}{ \sqrt[10]{ {3}^{5} } } = \frac{6. \sqrt[10]{ {3}^{5} } }{ \sqrt[10 ]{3 {}^{5} } . \sqrt[10]{ {3}^{5} } } = \frac{6. \sqrt[10]{3 {}^{5} } }{ \sqrt[10]{ {3}^{5 + 5} } } =$

$\frac{6. \sqrt[10]{ {3}^{5} } }{ \sqrt[10]{ {3}^{10} } } = \frac{6. \sqrt[10]{ {3}^{5} } }{3} = 2. \sqrt[10]{ {3}^{5} }$


$b) = \frac{2}{ \sqrt{13} + \sqrt{7} } = \frac{2. (\sqrt{13} - \sqrt{7} )}{ (\sqrt{13} + \sqrt{7}).( \sqrt{13} - \sqrt{7}) } =$

$\frac{2(. \sqrt{13} - \sqrt{7}) }{13 - 7} = \frac{2.( \sqrt{13} - \sqrt{7} ) }{6} = \frac{ \sqrt{13} - \sqrt{7} }{3}$