Question

racionalize as fracoes 1 sobre 2+ raiz de 3​

Answer 1

Explicação passo-a-passo:

$\dfrac{1}{2+\sqrt{3}}=\dfrac{1}{2+\sqrt{3}}\cdot\dfrac{2-\sqrt{3}}{2-\sqrt{3}}$

$\dfrac{1}{2+\sqrt{3}}=\dfrac{2-\sqrt{3}}{2^2-(\sqrt{3})^2}$

$\dfrac{1}{2+\sqrt{3}}=\dfrac{2-\sqrt{3}}{4-3}$

$\dfrac{1}{2+\sqrt{3}}=\dfrac{2-\sqrt{3}}{1}$

$\dfrac{1}{2+\sqrt{3}}=2-\sqrt{3}$