Racionalizando a expressão
![\frac{2 + \sqrt{2} }{ \sqrt{2} + 1 } \frac{2 + \sqrt{2} }{ \sqrt{2} + 1 }](https://tex.z-dn.net/?f=+%5Cfrac%7B2+%2B++%5Csqrt%7B2%7D+%7D%7B+%5Csqrt%7B2%7D+%2B+1+%7D+)
encontramos :
a)2
b)√2-4
c)3√2
d)2+3√2
e)√2
Soluções para a tarefa
Respondido por
1
Boa tarde!
![\frac{2 + \sqrt{2} }{ \sqrt{2 + 1} } \frac{2 + \sqrt{2} }{ \sqrt{2 + 1} }](https://tex.z-dn.net/?f=+%5Cfrac%7B2+%2B+%5Csqrt%7B2%7D+%7D%7B+%5Csqrt%7B2+%2B+1%7D+%7D+)
![\frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{( \sqrt{2} + 1) \times ( \sqrt{2} - 1) } \frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{( \sqrt{2} + 1) \times ( \sqrt{2} - 1) }](https://tex.z-dn.net/?f=+%5Cfrac%7B%282+%2B+%5Csqrt%7B2%7D%29+%5Ctimes+%28+%5Csqrt%7B2%7D+-+1%29+%7D%7B%28+%5Csqrt%7B2%7D+%2B+1%29+%5Ctimes+%28+%5Csqrt%7B2%7D+-+1%29+%7D+)
![\frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{2 - 1} \frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{2 - 1}](https://tex.z-dn.net/?f=+%5Cfrac%7B%282+%2B+%5Csqrt%7B2%7D%29+%5Ctimes+%28+%5Csqrt%7B2%7D+-+1%29+%7D%7B2+-+1%7D+)
![\frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{1} \frac{(2 + \sqrt{2}) \times ( \sqrt{2} - 1) }{1}](https://tex.z-dn.net/?f=+%5Cfrac%7B%282+%2B+%5Csqrt%7B2%7D%29+%5Ctimes+%28+%5Csqrt%7B2%7D+-+1%29+%7D%7B1%7D+)
![(2 + \sqrt{2}) \times ( \sqrt{2} - 1) (2 + \sqrt{2}) \times ( \sqrt{2} - 1)](https://tex.z-dn.net/?f=%282+%2B+%5Csqrt%7B2%7D%29+%5Ctimes+%28+%5Csqrt%7B2%7D+-+1%29)
![2 \sqrt{2} -2 + 2 - \sqrt{2} 2 \sqrt{2} -2 + 2 - \sqrt{2}](https://tex.z-dn.net/?f=2+%5Csqrt%7B2%7D+-2+%2B+2+-+%5Csqrt%7B2%7D+)
![2 \sqrt{2} - \sqrt{2} 2 \sqrt{2} - \sqrt{2}](https://tex.z-dn.net/?f=2+%5Csqrt%7B2%7D+-+%5Csqrt%7B2%7D+)
![\sqrt{2} \sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7D+)
R= e)
Espero ter ajudado!
R= e)
Espero ter ajudado!
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