Question

racionalizando 1-√3 / 2-√3 teremos ?

Answer 1

$\dfrac{1- \sqrt{3} }{2- \sqrt{3} } = \dfrac{(1- \sqrt{3}).(2+\sqrt{3}) }{(2- \sqrt{3}).(2+\sqrt{3}) } = \dfrac{2+\sqrt{3}-2\sqrt{3}-3 }{4-3} = \dfrac{-\sqrt{3}-1 }{1}$$=-\sqrt{3}-1$