Question

Racionaliza os denominadores das expressões

Me ajuda pfvvvvvvvv ❤️

Answer 1

Oie, tudo bom?

d)

$= \frac{1}{3 - \sqrt{6} } \\ = \frac{1}{3 - \sqrt{6} } \: . \: \frac{3 + \sqrt{6} }{3 + \sqrt{6} } \\ = \frac{1(3 + \sqrt{6} )}{(3 - \sqrt{6} ) \: . \: (3 + \sqrt{6} )} \\ = \frac{3 + \sqrt{6} }{3 {}^{2} - \sqrt{6} {}^{2} } \\ = \frac{3 + \sqrt{6} }{9 - 6} \\ \boxed{ = \frac{3 + \sqrt{6} }{3} }$

e)

$= \frac{2}{5 + \sqrt{3} } \\ = \frac{2}{5 + \sqrt{3} } \: . \: \frac{5 - \sqrt{3} }{5 - \sqrt{3} } \\ = \frac{2(5 - \sqrt{3}) }{(5 + \sqrt{3} ) \: . \: (5 - \sqrt{3} )} \\ = \frac{2(5 - \sqrt{3} )}{5 {}^{2} - \sqrt{3} {}^{2} } \\ = \frac{2(5 - \sqrt{3} )}{25 - 3} \\ = \frac{2(5 - \sqrt{3} )}{22} \\ \boxed{ = \frac{5 - \sqrt{3} }{11} }$

Att. NLE Top Shotta

Answer 2

Explicação passo-a-passo:

$d) \frac{1}{3 - \sqrt{6} } = \frac{1.(3 + \sqrt{6} )}{(3 - \sqrt{6}).(3 + \sqrt{6} ) } = \frac{3 + \sqrt{6} }{3 {}^{2} - ( \sqrt{6} ) {}^{2} } = \frac{3 + \sqrt{6} }{9 - 6} = \frac{3 + \sqrt{6} }{3}$

[tex]e) \frac{2}{5 + \sqrt{3} }

e) 2/5+V3= [2.(5-V3]/(2/5+V3).(2-5V3)=

2.(5-V3)

__________ = 2.(5-V3)/25-3=

5²-(V3) ²

2.5-V3/22= 5-V3/11