Question

QUESTÕES DE MATÉMATICA BÁSKARA PF 

x² - 16 =0


x² + 3x=0


4x² - 8x =0


x² - 4x + 6 =0


x² + 6x + 6 = -2

Answer 1

x² - 16 =0
x²= 16
x= √16
x=+- 4

x² + 3x=0
x(x+3)=0
x=0
x+3=0
x=-3


4x² - 8x =0
x(4x-8)=0
x=0
4x-8=0
4x=8
x=8/4
x=2


x² - 4x + 6 =0
Δ= -4² -4.1.6
Δ= 16-24
Δ= -8
x ñ pertence aos reais


x² + 6x + 6 = -2
x²+6x+6+2=0
x²+6x+8=0
Δ= 6² -4.1.8
Δ=36 - 32
Δ=4
√4=2
x= -6+2/2= -4/2= -2
x= -6-2/2= -8/2= -4