Question

QUESTÃO - NÍVEL: I

Dê a resolução e a alternativa correta do limite abaixo:

$\lim_{x\rightarrow 3} \frac{x^2-1}{x+1}$

$a)\ \frac{4}{5}\\\\b)\ 2\\\\c)\ \frac{5}{4}\\\\d)\ \frac{1}{2}\\\\e)\ \frac{2}{5}$

Answer 1

= 3²-1 /3+1
=9-1/4
=8/4
=2
..
letra b)
att:jhonny

Answer 2

$\mathsf{\lim_{x \to 3}\dfrac{{x}^{2}-1}{x+1}}$

$\mathsf{\lim_{x \to 3}\dfrac{(x-1)\cancel{(x+1)}}{\cancel{x+1}}}$

$\boxed{\boxed{\mathsf{\lim_{x \to 3}x-1=3-1=2}}}$