Question

QUESTAO EM ANEXO POR FAVOR ME AJUDEM

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Answer 1

$y=\frac{x+1}{x-1}\\ \\ y=\frac{u}{v}\\ \\ y'=\frac{u'.v-u.v'}{v^2}\\ \\ y'=\frac{x-1-(x+1)}{(x-1)^2}=\frac{-2}{(x-1)^2}\\ \\ y'(3)=\frac{-2}{(3-1)^2}=\frac{-2}{4}=-\frac{1}{2}$