Question

questão 5
a) ( ab - b+1) . ( ab+ a - 1) , para a= 4 e para b= -2

b) ( a + b + c) . ( a - b + c) . ( a - b - c) , para a= 1 , para b= -1 ,para c= 1

Answer 1

$a)\\\\(ab-b+1) . (ab+a-1 )\\a = 4; b = -2\\\\(4.-2 - ( -2 ) + 1 ) . ( 4.-2 + 4 -1 ) = (-8 + 2 + 1) . ( -8 +4 -1 ) = -5 . -5 = +25\\\\b)\\\\( a+b+c ) . (a-b+c ) . ( a-b-c) = \\a = 1; b= -1; c=1\\\\(1+(-1)+1) . (1-(-1) +1 ) . ( 1 -( -1) - 1 ) = (1-1+1 ) . (1+1+1 ). ( 1+1-1 ) = 1.3. 0 = 0$