Question

QUESTÃO 1




I. J.


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97b7a781fe2d0d777d833902fcafb0d6.docx

Answer 1

$\sqrt{ 2^{x+1} } = \frac{1}{ 4^{x+1} } \\ \\ ( \sqrt{ 2^{x+1} })^2 = (\frac{1}{ 4^{x+1} })^2 \\ \\ 2^{x+1} = \frac{1^2}{( 4^{x+1})^2 } \\ \\ 2^{x+1} = \frac{1}{4^{2x+2} } \\ \\ 2^{x+1} = 4^{-(2x+2)} \\ \\ 2^{x+1} = (2^{2) ^{-(2x+2)} } \\ \\ 2^{x+1} = 2^{-2(2x+2)} \\ \\ 2^{x+1} = 2^{-4x-4} \\ \\ x+1=-4x-4 \\ \\ x+4x=-4-1 \\ \\ 5x=-5 \\ \\ x=-1$