Question

QUESTÃO 04. Desenvolvendo o binômio (x + 1)⁵ obten - se? *

a) x⁵ + 10x⁴ + 5x³ + 10x² + 5x + 1
b) x⁵ + 5x⁴ + 10x³ + 10x² + 5x + 1
c) x⁵ + 5x⁴ + 10x³ + 20x² + 5x +5
d) x⁵ + 10x⁴ + 15x³ + 20x² + 15x + 3
e) x⁵ + 5x³ + 10x⁴ + 10x² + 5x + 1

Answer 1

Desenvolvendo o binômio (x + 1)⁵ obtém - se:

a) x⁵ + 10x⁴ + 5x³ + 10x² + 5x + 1

b) x⁵ + 5x⁴ + 10x³ + 10x² + 5x + 1  ⇒ alternativa correta

c) x⁵ + 5x⁴ + 10x³ + 20x² + 5x +5

d) x⁵ + 10x⁴ + 15x³ + 20x² + 15x + 3

e) x⁵ + 5x³ + 10x⁴ + 10x² + 5x + 1

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Desenvolvendo através do Binômio de Newton (em anexo).

$\left[\begin{array}{cc}5\\0\\\end{array}\right].x^{5}.1^{0}+\left[\begin{array}{cc}5\\1\\\end{array}\right].x^{4}.1^{1}+\left[\begin{array}{cc}5\\2\\\end{array}\right].x^{3} .1^{2} +\left[\begin{array}{cc}5\\3\\\end{array}\right].x^{2}.1^{3} +\left[\begin{array}{cc}5\\4\\\end{array}\right].x^{1} .1^{4}+\left[\begin{array}{cc}5\\5\\\end{array}\right] .x^{0}.1^{5}$=

$1.x^{5}.1^{0} +5.x^{4}.1^{1}+10.x^{3} .1^{2}+10.x^{2}.1^{3}+5.x^{1}.1^{4}+1.x^{0}.1^{5}$ =

$x^{5}+ 5.x^{4}+10x^{3}+10x^{2}+5x+1$

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Answer 2

Resposta:E a letra C

Explicação passo a passo: