Question

Quero só o cálculo ?

Answer 1

$\frac{x-3}{2} + \frac{1}{x} = -3$

$\frac{x^{2}- 3x}{2x} + \frac{2}{2x} = -3$

$\frac{x^{2}- 3x}{2x} + \frac{2}{2x} = \frac{-6x}{2x}$

$\frac{x^{2}- 3x}{2x} + \frac{2}{2x} - \frac{-6x}{2x} = 0$

$x^{2} - 3x + 2 - 6x = 0$

$x^{2} - 9x + 2 = 0$

$Δ = 81 - 8$

$Δ = 73$

$x = \frac{9+-\sqrt{73}}{2}$

$x^{2} = (\frac{9+-\sqrt{73}}{2})^{2}$