Question

quero saber qual sao os zeros da funçao x elevado a 2-5x+6

Answer 1

$F(x)= x^{2} -5x+6\to\\\\ x^{2} -5x+6=0\\\\ a=1;b=-5;c=6\\\\\\ \Delta=b^2-4ac\to \Delta=(-5)^2-4*1*6\to \Delta=25-24\to \Delta=1\\\\ x' \neq x''\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-5)\pm \sqrt{1} }{2*1} \to x= \frac{5\pm 1}{2} \to \\\\ x'= \frac{5\pm+ 1}{2} \to x'= \frac{6}{2} \to x'=3\\\\ x''= \frac{5- 1}{2} \to x''= \frac{4}{2} \to x''=2\\\\\\ S=(2;3)$

Answer 2

x^2-5x+6=0
delta=b^2-4ac
delta=(-5)^2-4.1.6
delta=25-24
delta=1
x=-b-/+ raiz de delta/2a
x=-(-5)-1/2.1
x=5-1/2
x=4/2
x=2
x=-(-5)+1/2.1
x=5+1/2
x=6/2
x=3