Question

Quero descobrir o delta da equacao 2x^2 - 8x + m

Answer 1

2x^2 - 8x + m = 0

Δ = b^2 - 4.a.c

Δ = (-8)^2 -4.2.m

Δ = 64 - 8m

64 - 8m = 0

-8m = -64

8m = 64

m = 64/8

m = 8

Δ = 64 - 8.8

Δ = 64 - 64 = 0