Question

Queria saber a simplificação dos Radicais 80,32,48,72

Answer 1

√80
80/2
40/2
20/2
10/2
05/5
01 --> 80 = 2^4 x 5 --> √80 = √2^4 x √5 = √16 x √5 = 4√5

√32 = √16 x √2 = 4√2

√48 = √16 x √3 = 4√3

√72 = √9 x √4 x √2 = 3 x 2√2 = 6√2

Answer 2

√80 = √16.√5 = 4√5

√32 = √16.√2 = 4√2

√48 = √16.√3 = 4√3

√72 = √36.√2 = 6√2
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80: 2
40: 2
20: 2
10: 2
5: 5
1    =    2.2.2.2.5 = √16.√5 = 4√5

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32: 2
16: 2
8: 2
4: 2
2: 2
1       =   2.2.2.2.2 = 16.2 = √16.√2 = 4√2
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48: 2
24: 2
12: 2
6: 2
3: 3                          4
1    =  2.2.2.2.3 =   2    .  3   =   √16.√3 = 4√3

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72: 2
36: 2
18: 2
9: 3
3: 3                          3       2
1      =   2.2.2.3.3 = 2  .   3     =   2².2.3² = √4.√2.√9 = 2.√2.3 = 2.3√2 = 6√2