Question

queria calcular logaritmo
de 3(2+log 3 5)
Obs é log de 5 na base 3

Answer 1

log 3 base2  =x
2x=3

log 5 base 3  = x
3x=5

Answer 2

$\log 5 = 0.698$
$\log 3 = 0.477$

$3(2+log_{3}5)$
$3(2+\frac{\log5}{\log3})$
$6+\frac{3\log5}{\log3}$
$6+\frac{3*0.698}{0.477}$
$6+\frac{2.096}{0.477}$
$6+4.394$
$10.39$