Question

Quem sabe essa? valendo 20pts
Resolver as equações abaixo usando a fórmula de bháskara

Answer 1

Vamos lá.

a)

$x^2-5x+6=0\\\\Coeficientes:\;a=1,\;b=-5\;e\;c=6\\\\\Delta=b^2-4ac\\\Delta=-5^2-4\cdot1\cdot(6)\\\Delta=25-24\\\Delta=1\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{1}}{2\cdot1}\\\\x=\dfrac{5\pm1}{2}\\\\x_1=\dfrac{5+1}{2}=\dfrac{6}{2}=3\\\\x_2=\dfrac{5-1}{2}=\dfrac{4}{2}=2$

b)

$x^2+2x-3=0\\\\Coeficientes:\;a=1,\;b=2\;e\;c=-3\\\\\Delta=b^2-4ac\\\Delta=2^2-4\cdot1\cdot(-3)\\\Delta=4+12\\\Delta=16\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-2\pm\sqrt{16}}{2\cdot1}\\\\x=\dfrac{-2\pm4}{2}\\\\x_1=\dfrac{-2+4}{2}=\dfrac{2}{2}=1\\\\x_2=\dfrac{-2-4}{2}=\dfrac{-6}{2}=-3$

Espero ter ajudado