Question

Quem puder ajudar, serei grata!!!;)❣️
cálculos e respostas, por favor*​

Answer 1

Resposta:

a) -30a²b³c⁶

b) 4x³

c) $\frac{2}{5} x$

d) -4⁶c²

e) $\frac{3}{2} a$

Explicação passo a passo:

a) (5bc³)(-b²c)(6a²c²) = -5b³c⁴(6a²c²) = -5a²b³c⁶

b) $\frac{20x^{4} }{5x} = \frac{4x^{4} }{x} = 4x^{3}$

c) $(\frac{2}{7} ax^{3} ) : (\frac{5}{7} ax^{2} ) = \frac{\frac{2}{7} ax^{3} }{\frac{5}{7} ax^{2} } = \frac{2ax^{3} }{7} . \frac{7}{5ax^{2} } = \frac{2x}{5}$

d) $(-4a^{2}c^{5} ) ^{4} : (\frac{1}{4} a^{4}c^{9}) ^{2} = \frac{-4^{4} a^{8}c^{20} }{\frac{1}{4^{2} }a^{8} c^{18} } = \frac{-4^{4}c^{20} }{4^{-2}c^{18} } = -4^{6} c^{2}$

e) $\frac{45ab}{30b} = \frac{9a}{6} = \frac{3a}{2}$