Question

quem aí pode ajudar pfv​

Answer 1

Resposta:

Letra B.

Explicação passo-a-passo:

$\boxed{a^{-1}=\dfrac{1}{a}}\\\\ \bigg(-\dfrac{3}{2}\bigg)^{-2}-\bigg(+\dfrac{2}{3}\bigg)^{-1}=\bigg(-\dfrac{2}{3}\bigg)^2-\bigg(+\dfrac{3}{2}\bigg)^1=\\\\ = \dfrac{4}{9}-\dfrac{3}{2}=\dfrac{8-27}{18}=\boxed{-\dfrac{19}{18}}$