Question

quantos termos tem uma P.G (3,6,12,...,3072)?

Answer 1

q=6/3=2
3072=a1*q^n-1
3072=3*2^n-1
3072/3=2^n-1
1024=2^n-1
2^^10=2^n-1
n-1=10
n=10+1
n=11
são 11 termos