Question

Quantos termos tem a P.G (3,6...,1536)

Answer 1

Resposta:

10 termos

Explicação passo-a-passo:

q= 6/3 = 2

$a_{n}=\frac{a_{1(q^{n-1}) } }{q-1}\\\\1536=\frac{3(2^{n-1}) }{2-1}\\\\1536=3(2^{n-1})\\\\512= 2^{n-1}\\\\2^{9}=2^{n-1}\\\\n-1=9\\\\n=10$