Question

quantos termos existem na p.g (3,6..., 1536 ?

Answer 1

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$a_n=1536 \\ a_1=3 \\ r=q=6\div3=2 \\ n=? \\ \\ termo~~geral \\ \\ a_n=a_1.q^{n-1} \\ \\ 1536=3.2^{n-1} \\ 1536\div3=2^{n-1} \\ 512=2^{n-1} \\ \\ \not2^{n-1}=\not 2^9 \\ \\ n-1=9 \\ n=9+1 \\ n=10~~termos$