Question

quantos termos da P.G.(3,6,12,...)devemos somar a fim de que o total resulte 49149?

Answer 1

q=a2/a1

q=6/3

q=2

sn=a1.(q^n-1)/(q-1)

3.(2^n-1)/(2-1)=49.149

(2^n-1)/1=49.149/3

(2^n-1)=16.383

2^n=16.383+1

2^n=16.384

2^n=2^14

n= 14

Devemos somar 14 termos