Question

Quantos termos a p.g (2,6,18....13122)

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{6}{2} = 3 \\ \\ = = = = = = = = = = = = = = \\ \\ > numero \: de \: termos \: da \: pg$

$an = a1 \times q {}^{n - 1} \\ 13122 = 2 \times 3 {}^{n - 1} \\ \frac{13122}{2} = 3 {}^{n - 1} \\ 6561 = 3 {}^{n - 1} \\ 3 {}^{8} = 3 {}^{n - 1} \\ n - 1 = 8 \\ n = 8 + 1 \\ n = 9$

Resposta: PG de 9 termos

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