Question

quantos temos tem progressão aritmética 7, 11, 787?​

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: aritmetica \\ \\ r = a2 - a1 \\ r = 11 - 7 \\ r = 4 \\ \\ \\ an = a1 + (n - 1)r \\ 787 = 7 + (n - 1)4 \\ 787 = 7 + 4n - 4 \\ 787 = 3 + 4n \\ 787 - 3 = 4n \\ 784 = 4n \\ n = \frac{784}{4} \\ n = 196 \\ \\ \\ resposta \: > \: \: pa \: \: de \: \: 196 \: \: \: termos \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$