Question

quantos numeros reais inteiro exitem entre as raizes da equaçao [tex] x^2-2x-15=0

Answer 1

$x^2-2x-15=0\\ \Delta=(-2)^2-4*1*(-15)\\ \Delta=4+60\\ \Delta=64\\ x=\dfrac{-(-2)\pm \sqrt{64} }{2*1}\\\\ x'=\dfrac{2+8}{2}=\boxed{5}\\\\ x''\dfrac{2-8}{2}=\boxed{-3}\\\\ \ [-3,~5] = \{-2,-1,0,1,2,3,4\}$

7 números inteiros entre as raízes.