Question

quantos mols existem em: 1368 gramas de C12H22O11

Answer 1

C12H22O11 = 12 x 12 + 1 x 22 + 16 x 11 = 342 g/mol

1 mol C12H22O11 ----------- 342 g
x mol C12H22O11 ----------- 1368 g

x  = 1368 / 342

x = 4,0 mols