Question

quanto que e X2-5X-14

Answer 1

$x^{2} - 5x - 14$
Usando bhaskara:
Δ = $b^{2} - 4ac$
a= 1
b= - 5
c= -14
Δ = $(-5)^{2} - 4 (1) (-14)$
Δ = 25 + 56
Δ = 81

x= -b +- √Δ/2a

x=  5 +- √81/2
x1= 5 + 9/2
x1= 14/2
x1= 7

x2= 5 - 9/2
x2= -4/2
x2= -2
 
Espero ter ajudado!

Answer 2

x²-5x-14

∆=b²-4.a.c
∆=(-5)²-4.1.(-14)
∆=25-(-56)
∆=25+56=81.

x=(-b±√∆)/2.a

x=-(-5±√81)/2.1
x=(5±9)/2

x1= (5+9)/2
x1=14/2
x1=7

x2=(5-9)/2
x2=-4/2
x2=-2

S=(-2,7)