Question

Quanto que e 2x²-18x=0

Answer 1

$2x^2-18x=0\\\\a=2\\b=-18\\c=0\\\\Delta=b^2-4*a*c\\Delta=(-18)^2-4*2*0\\Delta=324-0\\Delta=324\\\\x= \frac{-b \frac{+}{} \sqrt{Delta} }{2*a}\\\\x= \frac{-18 \frac{+}{} \sqrt{324} }{2*2}\\\\ x= \frac{-18 \frac{+}{} 18}{4}\\\\x^{I}= \frac{-18+18 }{4} = \frac{0}{4}= 0\\\\x^{II}= \frac{-18-18}{4}= \frac{-36}{4}=-9\\\\S=(0,-9)$