Question

quanto mede o ângulo interno de um poligono de 14 lados

Answer 1

$\alpha = \frac{180(n -2)}{n}\\\\ \alpha = \frac{180(14 - 2)}{14} \\\\ \alpha = \frac{2520-360}{14} \\\\ \alpha = \frac{2160}{14} \to \alpha \approx 154,29^{\circ}$