Question

Quanto fica (5+3b)² Me ajudem

Answer 1

Ola

(5+3b)²=0

(5+3b)(5+3b)=0

25+15b+15b+9b²=0

9b²+30b+25=0

a=9 ; b=30 e c=25

Lembrando que:

∆ = b²—4*a*c

∆ = 30²—4*9*25
∆ = 900 — 900
∆ = 0

x1,2 = (—b±√∆)/2*a

x1,2 = (—30±√0)/2*9
x1,2 = (—30±0)/18


x1=(—30+0)/18
x1 = —30/18
x1 = —5/3

x2 = (—30—0)/2*9
x2 = —30/18
x2 = —5/3

Dúvidas??Comente!!

Answer 2

(5 + 3b)²

( 5 + 3b) • (5 + 3b)

25 + 15b + 15b + 9b²

25 + 30b + 9b²

9b² + 30b + 25