Question

Quanto é X2+6×+8=0?
(X ao Quadrado)

Answer 1

$x^{2} +6x+8=0\\\\\\ a=1;b=6;c=8\\\\\\ \Delta= b^{2} -4ac\to \Delta= 6^{2} -4*1*8\to \Delta= 36-32\to \Delta= 4\\\\\\\\ x= \frac{-b+- \sqrt{\Delta} }{2a} \to\\\\ x= \frac{-6+- \sqrt{4} }{2*1} \to \\\\ x= \frac{-6+- 2 }{2} \to \\\\\\\\ x'= \frac{-6+ 2 }{2} \to \\\\ x'= \frac{-4 }{2} \to \\\\ x'= -2\\\\\\\\ x''= \frac{-6- 2 }{2} \to \\\\x''= \frac{-8 }{2} \to \\\\x''= -4\\\\\\\\ S=(-4,-2)$