Question

quanto e x²-10x+25=0

Answer 1

x^2-10x+25=0
delta=b^2-4ac
delta=(-10)^2-4.1.25
delta=100-100
delta=0
x=-b-/+ raiz de delta/2a
x=-(-10)-0/2.1
x=10-0/2
x=10/2
x=5
S={5}

Answer 2

Resposta:

$S=\{5\}$

Explicação passo-a-passo:

$x^{2} -10x+25=0\\\\a=1\\b=(-10)\\c=25$

$\Delta=b^{2} -4ac\\\Delta=(-10)^{2}-4\times1\times25\\\Delta=100-100\\\Delta=0$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-10)\pm\sqrt{0} }{2\times1} \\\\x=\frac{10\pm0}{2}$

$x_{1} =\frac{10+0}{2} =\frac{10}{2} =5\\\\x_{2}=\frac{10-0}{2}=\frac{10}{2} =5$