Question

quanto e (x+3x+2*)*(2x+3+5?

Answer 1

(4x+2)×(2x+8)
$8 {x}^{2} + 32x + 4x + 16 \\ 8 {x}^{2} + 36x + 16 \\ delta = {36}^{2} - 4 \times 8 \times 16 \\ delta = 1296 - 512 \\ delta = 784 \\ x1 = \frac{ - 36 + 28}{16} = - 0.5 \\ x2 = \frac{ - 36 - 28}{16} = - 4$