Question

quanto é:
(x+2).(x+3)=0

Answer 1

$(x + 2).(x + 3) = 0 \\ {x}^{2} + 3x + 2x + 6 = 0 \\ {x}^{2} + 5x + 6 = 0 \\ \delta = {5}^{2} - 4(1)(6) \\ \delta = 25 - 24 \\ \delta = 1$
$x = \frac{ - 5 + - \sqrt{1} }{2} \\ {x}^{1} = \frac{ - 4}{2} = - 2 \\ {x }^{2} = \frac{ - 6}{2} = - 3$
Pronto!!