Question

Quanto é que dá:
(tgx + tgy) ÷ (cotgx + cotgy) =

Answer 1

$\frac{tg \: x}{tg \: y} = \frac{ \cot(x) }{ \cot(y) } \\ \\ \frac{ \frac{sen \: x}{ \cos \: x } }{ \frac{sen \: y}{ \cos \: y } } = \frac{ \frac{cos\: x}{sen \: x} }{ \frac{cos \: y}{sen \: y} }$
1