Question

Quanto é:

(pi + 2)^-2

Answer 1

$(\pi + 2)^2=\pi^2 + 2 \cdot\pi \cdot2+2^2=\pi^2 + 4\pi +4\\ \\ \\(\pi + 2)^{-2}= (\frac{1}{\pi + 2})^2= \frac{1}{\pi^2 + 4\pi +4}$

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Utilizando π = 3,14 (valor aproximado)
$\\(\pi + 2)^{-2}= (\frac{1}{\pi + 2})^2=(\frac{1}{3,14 \ + \ 2})^2=(\frac{1}{5,14})^2\approx 3,785$