Question

quanto e 2x² - 8x + 8=0

Answer 1

2x²-8x+8=0              (2x²= 2x.2x= 4x
2x²-8x=0-8
4x-8x=0-8
-4x=0-8
-4x=0

Answer 2

$2 {x}^{2} - 8x + 8 = 0 \\ \\ a = 2 \\ b = ( - 8) \\ c = 8 \\ \\ \Delta = {b}^{2} - 4ac \\ \Delta = {( - 8)}^{2} - 4 \times 2 \times 8 \\\Delta = 64 - 64 \\ \Delta = 0 \\ \\ x = \frac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ x = \frac{ - ( - 8)\pm \sqrt{0} }{2 \times2} \\ \\ x = \frac{8\pm\diagup\!\!\!\!0}{4} \\ \\ x_{1 \: e \: 2} = \frac{8}{4} = 2$

S = {2}