Question

quanto e (2x+4)(x+3) meajudem pfv glr

Answer 1

(2x+4)(x+3)

2x²+6x+4x+12
2x²+10x+12=0

Δ= b²-4.a.c
Δ= 10²-4.2.12
Δ= 100-96
Δ= 4

X= -b+-√Δ
________
2.a

X= -10+-√4
______
2.2

X=-10+-2
____
4
Valores de X1 e X2:

X1= -10+2
_____
4
X1= -8/4
X1= -2


X2=-10-2
_____
4
X2= -12/4
X2=-3

Resultado: ( -2, -3 )

Espero ter ajudado;)
Bons estudos❤❤

Answer 2

2x + 4= x +3 
2x - x + 4 + 3
x = 1