Question

Quanto é {-20. [2²+3² -√400+(√25-3²)]}

Answer 1

{-20.[2^2+3^2-V400+(V25-3^2)]}=
{-20.[4+9-20+(5-9)]}=
{-20.[4+9-20+(-4)]}=
{-20.[4+9-20-4]}=
{-20.[13-20-4]}=
{-20.[-7-4]}=
{-20.[-11]}=
{-20.-11}=
+220