Question

Quanto é (2-² + 4-²) + (2-¹ + 4-¹)?

Answer 1

Resposta:17/16 

(2-² + 4-²) + (2-¹ + 4-¹)=

 $(2^{-2} + 4^{-2}) + (2^{-1}+4^{-1})=\\ (\frac{1^{2}}{2^{2}}+ \frac{1^{2}}{4^{2}} )+( \frac{1}{2}+ \frac{1}{4} ) =\\ \frac{1}{4}+ \frac{1}{16}+ \frac{1}{2}+ \frac{1}{4}=\\ \frac{2}{4}+ \frac{1}{16}+ \frac{1}{2}=\\ \frac{1}{2}+ \frac{1}{2}+ \frac{1}{16}=\\ \frac{2}{2}+ \frac{1}{16}=\\ 1+ \frac{1}{16}=\\ \frac{16+1}{16}=\\ \frac{17}{16}$